112k views
1 vote
If a duration of 0.05 second was selected for a particular exposure, what milliamperage would be necessary to produce 30 mAs?

600

User Jordon
by
7.8k points

1 Answer

4 votes

Final answer:

To produce 30 milliampere-seconds (mAs) with a duration of 0.05 seconds, you would need a current of 600 milliamperes (mA).

Step-by-step explanation:

If a duration of 0.05 seconds was selected for a particular exposure, and we need to produce 30 milliampere-seconds (mAs), we can calculate the necessary milliamperage to achieve this. The formula to calculate milliampere-seconds is:

milliampere-seconds (mAs) = current in milliamperes (mA) × time in seconds (s)

To find the current in milliamperes, we rearrange the formula:

current (mA) = milliampere-seconds (mAs) / time (s)

By substituting the given values, we get:

current (mA) = 30 mAs / 0.05 s =

600 mA

Therefore, the required milliamperage to produce 30 mAs with a duration of 0.05 seconds is 600 milliamperes.

User Manna
by
7.7k points