88.7k views
0 votes
You have 9.3 mL of a 0.031 M solution of NaOH. If you add this solution to 8.5 mL of a 0.012 M solution of crystal violet, what is the initial concentration of NaOH in the reaction mixture?

User Alfa
by
8.0k points

1 Answer

14 votes

Answer:

0.016M is the initial concentration of NaOH in the reaction mixture

Step-by-step explanation:

The NaOH is diluted from 9.3mL to 9.3mL + 8.5mL = 17.8mL. That is a dilution of:

17.8mL / 9.3mL = 1.914 times

As the initial concentration of the NaOH solution is 0.031M and is diluted 1.914 times, the final concentration of the NaOH solution is:

0.031M / 1.914 =

0.016M is the initial concentration of NaOH in the reaction mixture

User Stafox
by
7.1k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.