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1. Find the sum of the measures of the interior

angles of the indicated convex Polygon
B) 16-gon
A) 14-gon

1 Answer

10 votes

Answer:

A) Sum of angles in the 14-gon =
2160^(o)

B) Sum of angles in the 16-gon =
2520^(o)

Explanation:

Convex polygon is one that has the value of its internal angles less than the sum of angles in a triangle. That is each interior angle is less than
180^(o).

Sum of angles in a polygon = (n - 2) x
180^(o)

where n is the value of its number of sides.

So that;

A) 14-gon (which has 14 sides),

Sum of angles in the 14-gon = (14 - 2) x
180^(o)

= 12 x
180^(o)

=
2160^(o)

The sum of the measure of the interior angles of the 14-gon is
2160^(o).

B) 16-gon (which has 16 sides),

Sum of angles in the 16-gon = (16 - 2) x
180^(o)

= 14 x
180^(o)

=
2520^(o)

The sum of the measure of the interior angles of the 16-gon is
2520^(o).

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