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A large balloon fashioned to look like a mole is designed for the Macy’s Thanksgiving Day Parade. If the volume of the balloon is 835 L after the addition of 588 moles of helium, how many more moles of helium must be added to fill the balloon to its final volume of 2953 L?

User Mnk
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Final answer:

To fill the balloon to its final volume of 2953 L from 835 L, an additional 1494 moles of helium are required.

Step-by-step explanation:

The question asks about how many more moles of helium need to be added to a balloon to increase its volume from 835 liters to 2953 liters.

We can use Avogadro's law which states that the volume of a gas is directly proportional to the number of moles of the gas when the pressure and temperature are held constant.

Initial volume (V1): 835 L
Initial moles (n1): 588 moles
Final volume (V2): 2953 L
The question asks for the final moles (n2).

According to Avogadro's Law, V1/n1 = V2/n2.
Let's rearrange the formula to solve for n2: n2 = V2 x (n1/V1)
So, n2 = 2953 L x (588 moles / 835 L)

= 2082 moles

The mole that was originally in the balloon is still there, so we subtract the original amount of moles to find the additional moles needed:
Additional moles needed = n2 - n1
Additional moles needed = 2082 moles - 588 moles

= 1494 moles

User Yazan Rawashdeh
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