Question

A salt of KCl, potassium chloride, is dissolved in a beaker of an unknown solution. It is less soluble in the unknown solution than it is in a beaker of water at the same temperature. What explains the lack of solubility in the beaker of unknown solution?

a) the solution in the unknown beaker is at a pH of 7, which reduces the ability of the salt to dissolve

b) the solution in the unknown beaker is organic, reducing the ability of the salt to dissolve in the beaker

c) the solution in the unknown beaker is polar, causing a reduction in the ability of the salt ions to dissociate

d) the solution in the unknown beaker is 0.5 NaCl, and the common chloride ion is reducing the solubility of the KCL

Answer 1

D) The solution in the unknown beaker is 0.5NaCL, and the common chloride ion is reducing the solubility of the KCL .

Explanation: Just got it correct on USATESTPREP :)