Question

A ring is submerged in a graduated cylinder originally filled with exactly 48.0 mL of water. Using the final reading of the graduated cylinder, find the volume of the ring?

1) 0.6 mL
2) 0.7 mL
3) 3.0 mL
4) 3.6 mL

Answer 1

The volume of the ring is found by subtracting the initial water level in the graduated cylinder from the final water level after submerging the ring. The example provided gives a volume of 3.0 mL for Option 3. The large piece of jewelry has a density of 10.52 g/mL, indicating it could be made of a substance like silver.

Step-by-step explanation:

To find the volume of the ring submerged in the graduated cylinder, we use the principle of displacement. Initially, the graduated cylinder contains 48.0 mL of water. After submerging the ring, the final water reading will be higher. By subtracting the initial water level from the final water level, we obtain the volume of the ring. For example, if the final reading is 51.0 mL, then the volume of the ring would be 51.0 mL - 48.0 mL = 3.0 mL (Option 3).

For the large piece of jewelry with a mass of 132.6 g submerged in water originally at 48.6 mL, the final volume reads 61.2 mL, indicating a volume displacement of 61.2 mL - 48.6 mL = 12.6 mL. To determine the density of the jewelry, we use the formula: density = mass/volume, which would be 132.6 g / 12.6 mL = 10.52 g/mL. Assuming the jewelry is made of only one substance, the density suggests it could be made of a metal such as silver, which has a density close to this value.