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STT 8.4 The end of a spring is pulled to the right by 4 cm; the restoring force is 8 N to the left. Given the relationships shown in figure 8.14 c , if the spring is returned to equilibrium and then pushed to the left by 2 cm, the restoring force is A 4 N to the left

B 4 N to the right
C 8 N to the left
D 8 N to the right
E 16 n to the left
D 16 N to the right

User Ben Allred
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1 Answer

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Final answer:

The restoring force of a spring is proportional to its displacement from equilibrium. When displaced by 2 cm to the left, the spring exerts a 4 N restoring force to the right.

Step-by-step explanation:

The restoring force of a spring is directly proportional to the displacement from its equilibrium position as defined by Hooke's Law, which is given by the formula F = -kx, where F is the force exerted by the spring, k is the spring constant, and x is the displacement. In this scenario, given that when the spring was displaced by 4 cm (0.04 m) to the right there was a restoring force of 8 N to the left, if we were to displace it by 2 cm (0.02 m) to the left, we would expect half the force since the displacement is halved, maintaining the direct proportionality. Therefore, the restoring force will be 4 N to the right, which matches option B in the set of given answers.

User Lamisha
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