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13.38 An object floats in water with 75 % of its volume submerged. What is it's approx. density?

A 250 Kg/m^3
B 750
C 1000
D 1250 Kg/M^3

User Rea
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1 Answer

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Final answer:

The approximate density of an object that floats with 75% of its volume submerged in water is 750 kg/m³, which is 75% of the density of water.

Step-by-step explanation:

If an object floats in water with 75% of its volume submerged, this means that the buoyant force is equal to the weight of 75% of the object's volume of water. Since the object is in equilibrium, the weight of the object is equal to the buoyant force. The density of water is approximately 1000 kg/m³. To find the object's density, we can set up the following proportion since density equals mass divided by volume (ρ = m/V):

Object's density / Density of water = Volume of water displaced / Total volume of the object

0.75 (since 75% is submerged) = Volume of water displaced / Total volume of the object

Therefore, the object's density is 0.75 times the density of water. So, the object's density formula is:

Object's density = 0.75 × 1000 kg/m³

Object's density = 750 kg/m³

Thus, answer B 750 kg/m³ is the approximate density of the object when 75% of its volume is submerged in water.

User DL Narasimhan
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