Final answer:
The approximate density of an object that floats with 75% of its volume submerged in water is 750 kg/m³, which is 75% of the density of water.
Step-by-step explanation:
If an object floats in water with 75% of its volume submerged, this means that the buoyant force is equal to the weight of 75% of the object's volume of water. Since the object is in equilibrium, the weight of the object is equal to the buoyant force. The density of water is approximately 1000 kg/m³. To find the object's density, we can set up the following proportion since density equals mass divided by volume (ρ = m/V):
Object's density / Density of water = Volume of water displaced / Total volume of the object
0.75 (since 75% is submerged) = Volume of water displaced / Total volume of the object
Therefore, the object's density is 0.75 times the density of water. So, the object's density formula is:
Object's density = 0.75 × 1000 kg/m³
Object's density = 750 kg/m³
Thus, answer B 750 kg/m³ is the approximate density of the object when 75% of its volume is submerged in water.