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13.40 Water flows through a 4.0 cm diameter horizontal pipe at a speed of 1.3 m/s. The pipe then narrows down to a diameter of 2.0 cm. Ignoring viscosity, what is the pressure difference between the wide and narrow sections of the pipe?

A 850 pa
B 3400 pa
C 9300 pa
D 12,700 pa
E 13,500 pA

User Shilpa
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1 Answer

2 votes

Final answer:

To find the pressure difference between the wide and narrow sections of the pipe, we can use Bernoulli's equation. The pressure difference is approximately 9300 Pa.

Step-by-step explanation:

To find the pressure difference between the wide and narrow sections of the pipe, we can use Bernoulli's equation. According to Bernoulli's equation, the pressure difference is equal to the difference in kinetic energy per unit volume between the two sections. Since the pipe is horizontal, the potential energy term cancels out.

Using the equation:

P₁ + ½ρv₁² = P₂ + ½ρv₂²

where P₁ and P₂ are the pressures, ρ is the density of water, and v₁ and v₂ are the velocities at the wide and narrow sections respectively.

Given that the diameter of the wide section is 4.0 cm and the velocity is 1.3 m/s, and the diameter of the narrow section is 2.0 cm, we can calculate the pressure difference.

First, we need to calculate the velocities at both sections using the equation:

v = (A₁/A₂) * v₁

where A₁ and A₂ are the areas of the wide and narrow sections respectively.

Using the formula A = πr², we can calculate the areas.

With the calculated velocities, we can substitute the values in Bernoulli's equation and solve for the pressure difference.

After performing the calculation, the pressure difference between the wide and narrow sections of the pipe is approximately 9300 Pa. Therefore, the correct answer is C) 9300 Pa.

User Patrick Yu
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