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Four objects move with the velocity-versus-time graphs shown. Which object has the largest displacement between t=0 and t=2s?

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Final answer:

To identify the object with the largest displacement between t=0 and t=2 seconds, calculate the area under the velocity vs. time graph for each object. The largest area indicates the largest displacement, typically associated with a graph showing positive and increasing velocity.

Step-by-step explanation:

The question pertains to analyzing velocity vs. time graphs to determine which of the four objects has the largest displacement between t=0 and t=2 seconds. To find displacement from a velocity vs. time graph, one must calculate the area under the graph between the specified times. Since displacement is the area under the velocity vs. time graph, the object with the largest area under the curve from t=0 to t=2 seconds will have the largest displacement. Given that a flat line on a velocity vs. time graph indicates zero velocity and hence no displacement, any object with such a graph for the first two seconds will not move.

If we are shown a graph where the object's slope is increasing with time, this means the object is accelerating, indicating a larger displacement over time. Hence, among the given objects, the one with the graph showing a positive slope that increases in steepness between t=0 and t=2 seconds would have the largest displacement. It's important to note that without the actual graphs to refer to, we cannot definitively identify which object has the largest displacement, but we can understand the principles that would allow us to do so.

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