Question

A ball is thrown at an initial angle of 37 Degrees and initial velocity reaches a max. height H, as shown in figure Q 3.23. With what initial speed must a ball be thrown straight up to reach the same max. height H?

A 13.8 M/S
B 17.3 M/S
C 18.4 M/S
D 23.0 M/S

Answer 1

To reach the same maximum height as an angled throw, the ball must be thrown straight up with an initial speed of 0 m/s.

Step-by-step explanation:

To reach the same maximum height of H, the ball must reach its highest point with zero velocity. This means that the initial speed when thrown straight up should be equal to the final velocity when reaching the maximum height from the angle throw. Since the vertical component of the initial velocity at an angle of 37 degrees is given by Vs = V * sin(theta), where V is the initial velocity, we can find the initial speed for the straight upward throw by setting Vs equal to zero and solving for V:

0 = V * sin(37)

V = 0 / sin(37)

V = 0

Therefore, the ball must be thrown straight up with an initial speed of 0 m/s to reach the same maximum height H.