Question

DF has midpoint E(1, -3). if ID(0, 2), what are the coordinates of F?

Answer 1

F is at (2, -8)

Explanation:

use the midpoint formula: (sum of x-values/2, sum of y-values/2)

let (x,y) = coordinate of pt F

(0+x/2) = 1; x = 2

(2+y/2) = -3; 2 + y = -6; y = -8