Help Im not able to figure it out

asked Sep 7, 2024 101k views

3 votes

7.5k points

Please log in or register to add a comment.

3 votes

Answer:

$({ {2}^(8) {3}^(5) {6}^(0) })^( - 2) * {( \frac{ {3}^( - 2) }{ {2}^(3) }) }^(4) * {2}^(28) =$

${2}^( - 16) {3}^( - 10) * \frac{ {3}^( - 8) }{ {2}^(12) } * {2}^(28) =$

$\frac{1}{ {2}^(16) {3}^(10) } * \frac{1}{ {3}^(8) {2}^(12) } * {2}^(28) =$

$\frac{1}{ {3}^(18) }$

Jbu answered Sep 13, 2024

by Jbu

8.3k points

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

8.8m questions

11.4m answers