Answer:
0.6316
Explanation:
The computation of the probability that 2 people were excited without replacement is shown below:
There is a total of 20 people
out of which 16 are excited and the remaining 4 would be non-excited
Now the probability would be
![= (^(16)C_2)/(^(20)C_2)](https://img.qammunity.org/2022/formulas/mathematics/high-school/ljjvtg71yss4o0mr4aj1jiqx5bgayst9ar.png)
= 0.6316