Final answer:
For a demultiplexer with the selector bit set to 1 and both outputs at 0, the input must have been 0. It is the demultiplexer's function to direct a single input to one of several outputs based on the selector bits.
Step-by-step explanation:
If a demultiplexer selector bit is set to 1, and both outputs (a and b) are 0, then the input must have been 0. A demultiplexer takes a single input and channels it into one of several outputs. The selector bit or bits determine to which output the input will go. Since both outputs in the scenario are 0, and assuming the demultiplexer is functioning correctly, it indicates that the input was also 0.
If the demultiplexor selector bit is set to 1 and both outputs (a and b) are 0, then the input must have been 1.
For a demultiplexer with the selector bit set to 1 and both outputs at 0, the input must have been 0. It is the demultiplexer's function to direct a single input to one of several outputs based on the selector bits.