Final answer:
The crest-to-trough distance of a wave with an amplitude of 1 meter is 2 meters, which is twice the amplitude.
Step-by-step explanation:
The amplitude of a wave is defined as the maximum displacement from the equilibrium position. In a symmetrical wave, the amplitude is the distance from the equilibrium position to the crest or from the equilibrium to the trough. The crest-to-trough distance is therefore twice the amplitude. Given that the amplitude of the wave is 1 meter, the crest-to-trough distance, which is peak-to-trough distance, is 2 meters.