Question

I need to know this i’m confused

Answer 1

The magnitude (distance) of the vector is approximately
`\(51 \, \text{m}\).`

To find the magnitude (distance) of the vector given its components in the x and y directions
`(\(A_x\)` and
`\(A_y\))`, you can use the Pythagorean theorem. The magnitude
`(\(A\))` is given by:

`\[ A = √(A_x^2 + A_y^2) \]`

Given your values:

`\[ A_x = 44.4 \, \text{m} \]`

`\[ A_y = 25.1 \, \text{m} \]`

Substitute these values into the formula:

`\[ A = \sqrt{(44.4 \, \text{m})^2 + (25.1 \, \text{m})^2} \]`

`\[ A = √(1971.36 + 630.01) \]`

`\[ A = √(2601.37) \]`

`\[ A \approx 51 \, \text{m} \]`

Therefore, the magnitude (distance) of the vector is approximately
`\(51 \, \text{m}\).`