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What type of transport mechanism is
involved in releasing of insulin from cell?

1 Answer

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Final answer:

The release of insulin from pancreatic beta cells involves exocytosis, a process triggered by elevated blood glucose levels, leading to a cascade of intra-cellular reactions and the eventual fusion of insulin-containing vesicles with the plasma membrane. Drug responses, such as those to sulfonylurea drugs, are affected by individual genetics which is a focus of personalized medicine. Insulin, upon executing its action, can be degraded by the liver or released back into extracellular space.

Step-by-step explanation:

The transport mechanism involved in the release of insulin from cells is known as exocytosis. When blood glucose levels rise, glucose enters the pancreatic beta cells via the GLUT2 channel, leading to ATP production, which in turn closes the potassium channels. This cessation in potassium outflow induces the opening of calcium channels, culminating in the exocytosis of insulin. After insulin binds to its receptor on target cells, a series of reactions are triggered that result in the translocation of GLUT4-containing vesicles to merge with the plasma membrane, enabling facilitated glucose transport into the cells.

Similarly, on the pharmacogenomic front, individual genetic variations can significantly affect the metabolic processing of drugs, such as sulfonylurea, which can also instigate insulin release by directly intervening in the potassium channel-closing pathway. Consequently, personalized medicine aims to tailor treatment based on genetic makeup to optimize therapeutic efficacy and minimize adverse effects.

Focusing on the dynamics between insulin and its receptors, post-binding events can lead either to degradation primarily by liver cells or to re-release into the extracellular environment. The degradation process includes endocytosis and the subsequent breakdown by insulin-degrading enzymes.

User Dominic Weiser
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