Final answer:
To produce 224g of calcium oxide, 400g of calcium carbonate is required according to stoichiometry and the law of conservation of mass.
Step-by-step explanation:
To calculate the mass of calcium carbonate (CaCO3) needed to produce 224g of calcium oxide (CaO), we must use stoichiometry based on the balanced chemical reaction. Consider the example where heating 10.0 grams of calcium carbonate (CaCO3) produces 5.6 g of calcium oxide (CaO). According to the law of conservation of mass, the mass of the reactants is equal to the mass of the products.
The balanced chemical equation for the decomposition of calcium carbonate is:
CaCO3 → CaO + CO2
From the given information: 10.0 g CaCO3 produces 5.6 g CaO.
We can set up a proportion to find the mass of calcium carbonate needed to produce 224 g of CaO:
(5.6 g CaO / 10.0 g CaCO3) = (224 g CaO / x g CaCO3)
Solving for x gives us:
x = (10.0 g CaCO3 / 5.6 g CaO) * 224 g CaO
x = 400 g CaCO3
Therefore, 400 g of calcium carbonate is required to produce 224 g of calcium oxide.