Question

Carson measured a line to be 2.2 inches long. If the actual length of the line is 2.3 inches, then what was the percent error of the measurement, to the nearest tenth of a percent?

Answer 1

The percent error of the measurement is approximately 4.35% to the nearest tenth of a percent.

Step-by-step explanation:

To calculate the percent error, we can use the formula:
Percent Error = (|Measured Value - Actual Value| / Actual Value) * 100%

In this case, the measured value is 2.2 inches and the actual value is 2.3 inches. Plugging these values into the formula, we get:
Percent Error = (|2.2 - 2.3| / 2.3) * 100%
Percent Error = (0.1 / 2.3) * 100% ≈ 0.0435 * 100% ≈ 4.35%

Therefore, the percent error of the measurement is approximately 4.35% to the nearest tenth of a percent.