Final answer:
To calculate the mass of sodium sulphate from sodium hydroxide, first determine the moles of NaOH and then use the stoichiometry of the reaction to find the moles and mass of sodium sulphate produced. 240g of NaOH will yield 426.12g of sodium sulphate, given unlimited sulphuric acid.
Step-by-step explanation:
Calculating the Mass of Sodium Sulphate from Sodium Hydroxide
To calculate the mass of sodium sulphate produced from 240g of sodium hydroxide, we first need to determine the molar mass of NaOH using atomic masses (Na = 22.990 g/mol, O = 15.999 g/mol, H = 1.008 g/mol). Adding these together gives us 39.997 g/mol for NaOH. Next, we use the balanced chemical equation: 2NaOH + H2SO4 -> Na2SO4 + 2H2O. From this, we can see that 2 moles of NaOH produce 1 mole of Na2SO4.
Firstly, calculate the moles of NaOH:
- Moles of NaOH = mass / molar mass = 240g / 39.997 g/mol = 6.000 moles of NaOH
Now, using the stoichiometry of the reaction where 1 mole of H2SO4 reacts with 2 moles of NaOH to produce 1 mole of Na2SO4, we find that 6.000 moles of NaOH would produce:
- 6.000 moles NaOH * (1 mole Na2SO4 / 2 moles NaOH) = 3.000 moles Na2SO4
To find the mass of Na2SO4, we calculate its molar mass (Na = 2*22.990 g/mol, S = 32.065 g/mol, O4 = 4*15.999 g/mol), which gives us 142.04 g/mol for Na2SO4. Then, the mass of Na2SO4 produced is:
- Mass of Na2SO4 = moles * molar mass = 3.000 moles * 142.04 g/mol = 426.12g of Na2SO4
Therefore, 240g of sodium hydroxide can produce 426.12g of sodium sulphate, assuming that sulphuric acid is unlimited and the reaction is complete.