Final answer:
To find the number of moles in 39g of Al(OH)3, the molar mass of Al(OH)3 is calculated to be 78.01g/mol. Dividing the mass of Al(OH)3 by its molar mass (39g / 78.01g/mol) gives us approximately 0.50 moles.
Step-by-step explanation:
To determine the number of moles in 39g of Al(OH)3, we must first calculate the molar mass of Al(OH)3. The molar mass of Al(OH)3 is derived from the atomic masses of aluminum (Al), oxygen (O), and hydrogen (H), which are 26.98g/mol, 16.00g/mol, and 1.01g/mol, respectively. Al(OH)3 has one aluminum atom, three oxygen atoms, and three hydrogen atoms. The molar mass is thus calculated as follows:
Molar mass of Al(OH)3 = 1(26.98g/mol) + 3(16.00g/mol) + 3(1.01g/mol) = 26.98g/mol + 48.00g/mol + 3.03g/mol = 78.01g/mol.
Now, using the molar mass, we can convert the mass of Al(OH)3 to moles:
Number of moles of Al(OH)3 = Mass of Al(OH)3 / Molar mass of Al(OH)3 = 39g / 78.01g/mol ≈ 0.50 moles.
Hence, there are approximately 0.50 moles in 39g of Al(OH)3.
To determine the number of moles in 39g of Al(OH)3, we need to use the molar mass of Al(OH)3. The molar mass can be calculated by adding up the atomic masses of the elements in the compound. The molar mass of Al is 26.98 g/mol, O is 16.00 g/mol, and H is 1.01 g/mol. Adding these masses together, we get:
Molar mass of Al(OH)3 = (26.98 g/mol × 1) + (16.00 g/mol × 3) + (1.01 g/mol × 3) = 78.00 g/mol
To find the number of moles, we can use the formula:
Number of moles = Mass of substance / Molar mass
So, for 39g of Al(OH)3:
Number of moles = 39g / 78.00 g/mol = 0.5 mol