Final answer:
0.25 moles of sodium chloride will be produced. The mass of sodium chloride produced is 14.61 g.
Step-by-step explanation:
To determine the number of moles of sodium chloride produced, we need to use the balanced chemical equation for the reaction between sodium hydroxide (NaOH) and hydrochloric acid (HCl):
NaOH + HCl -> NaCl + H2O
From the equation, we can see that the mole ratio between NaOH and NaCl is 1:1. Therefore, if 1 mole of NaOH reacts with 1 mole of HCl, then 1 mole of NaCl will be produced. Since we are given 1 mole of NaOH and 0.25 moles of HCl, we can conclude that 0.25 moles of NaCl will be produced.
To calculate the mass of sodium chloride produced, we need to know the molar mass of NaCl, which is 58.44 g/mol. To find the mass, we multiply the number of moles (0.25) by the molar mass (58.44 g/mol):
Mass of NaCl = 0.25 moles x 58.44 g/mol = 14.61 g