Question

A solution with 0.495 mol of pyridinium fluoride and enough water to make 1.00 L is prepared.

What is the molarity of the pyridinium fluoride in the solution?

A. 0.495 M
B. 0.990 M
C. 1.00 M
D. 2.00 M

Answer 1

The molarity of the pyridinium fluoride in the solution is calculated by dividing the moles (0.495 mol) by the volume of the solution (1.00 L), giving a molarity of 0.495 M, which corresponds to answer A.

Step-by-step explanation:

The molarity of a solution is defined as the number of moles of solute divided by the volume of the solution in liters. To calculate the molarity of the pyridinium fluoride, we divide the moles of pyridinium fluoride by the volume of the solution. There are 0.495 moles of pyridinium fluoride in a 1.00 L solution.

Therefore, the molarity (M) is:

Molarity = moles/volume = 0.495 mol / 1.00 L = 0.495 M

Hence, the correct answer is A. 0.495 M.