Question

A watch face has a 5/7 inch by 1/2 inch rectangular shape with a 1/3 inch gold encasing. What are the dimensions of the watch face, including the gold encasing? (Use the larger value for length and the smaller value for width .)

Answer 1

The dimensions of the watch face, including the gold encasing, can be calculated by adding the width of the watch face to twice the width of the gold encasing, and adding the length of the watch face to twice the length of the gold encasing.

Step-by-step explanation:

The dimensions of the watch face, including the gold encasing, can be calculated by adding the width of the watch face to twice the width of the gold encasing, and adding the length of the watch face to twice the length of the gold encasing.

Given that the watch face has a width of 5/7 inch and the gold encasing has a width of 1/3 inch, the total width would be 5/7 + 2 * 1/3 = 5/7 + 2/3 = 15/21 + 14/21 = 29/21 inch.

Similarly, given that the watch face has a length of 1/2 inch and the gold encasing has a length of 1/3 inch, the total length would be 1/2 + 2 * 1/3 = 8/12 + 4/12 = 12/12 = 1 inch.