Question

The tangent line to the graph of function h at the point (3,8) passes through the point (-1,0)

Find h'(3).
h'(3)=___

Answer 1

The slope of the tangent line to function h at the point (3,8) is 2.

Step-by-step explanation:

To find h'(3), we need to find the slope of the tangent line to the graph of function h at the point (3,8). Since the line passes through the point (-1,0), we can use the slope formula:

slope = (change in y) / (change in x)

Let's calculate the slope:

slope = (8 - 0) / (3 - (-1)) = 8 / 4 = 2

Therefore, h'(3) = 2.