111k views
4 votes
Find the horizontal asymptote of the function f(x)=−2x²+3x+6/x²+1​.

User Lech Birek
by
8.2k points

1 Answer

3 votes

Final answer:

The horizontal asymptote of the function f(x) = (-2x² + 3x + 6)/(x² + 1) is y = 0.

Step-by-step explanation:

The horizontal asymptote of the function f(x) = (-2x² + 3x + 6)/(x² + 1) can be found by observing the degrees of the numerator and denominator. Since the degree of the numerator is less than the degree of the denominator, the horizontal asymptote is y = 0. This means that as x approaches infinity or negative infinity, the function approaches 0.

User Hoakey
by
8.6k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.