Final answer:
The minimum value of the function f(x) = 4x² - 50x + 126 occurs at x = 6.25.
Step-by-step explanation:
Mathematics - High School
To find the minimum value of the function f(x) = 4x² - 50x + 126, we can use the vertex formula. The vertex formula states that for a quadratic function in the form f(x) = ax² + bx + c, the x-coordinate of the vertex can be found using the formula x = -b/(2a).
In this case, a = 4 and b = -50, so the x-coordinate of the vertex will be x = -(-50)/(2*4) = 50/8 = 6.25.
Therefore, the function f(x) reaches its minimum value at x = 6.25.