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The width of a rectangle is six meters less than its length. If the area of the rectangle is 112 m?, find the dimensions of the rectangle.

User Wad
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1 Answer

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Explanation:

the area of a rectangle is

length × width

in our case

length × width = 112 m²

and we know

width = length - 6

when using this in the first area equation we get

length × (length - 6) = 112

length² - 6×length = 112

length² - 6×length - 112 = 0

we know that for a general quadratic equation

ax² + bx + c = 0

the solution is

x = (-b ± sqrt(b² - 4ac))/(2a)

in our case

x = length

a = 1

b = -6

c = -112

length = (6 ± sqrt((-6)² - 4×1×-112))/(2×1) =

= (6 ± sqrt(36 + 448))/2 = (6 ± sqrt(484))/2 =

= (6 ± 22))/2 = 3 ± 11

length 1 = 3 + 11 = 14 m

length 2 = 3 - 11 = -8 m

a negative number does not make any sense for an actual length, so length 1 is the solution.

length = 14 m

width = length - 6 = 14 - 6 = 8 m

User Naqvitalha
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