Question

You are thinking a blue light of frequency 6.2x10¹⁴ Hz on the pice of metal causing electrons to be produces from the surface.

How much energy does each of the photons contain?"

Answer 1

The energy of each photon of blue light with a frequency of 6.2x10^14 Hz is 4.09 × 10^-19 J.

Step-by-step explanation:

The energy of a photon is given by the equation E = hf, where E is the energy, h is Planck's constant, and f is the frequency of the photon.

In this case, the frequency is given as 6.2x1014 Hz. Using the equation, we can calculate the energy:

E = (6.626 × 10-34 J-s) (6.2 × 1014 Hz) = 4.09 × 10-19 J

Therefore, each photon of blue light with a frequency of 6.2x1014 Hz contains an energy of 4.09 × 10-19 J.