Final answer:
The hang time for a basketball player jumping 1.0 m off the floor is 0.5 seconds, while for a jump of 0.3 m, the hang time is 0.275 seconds.
Step-by-step explanation:
The time in the air of a basketball player who jumps 1.0 m vertically off the floor can be calculated using the hang time equation, t = 0.5 √h. Plugging in the vertical height h = 1.0 m into the equation, we get t = 0.5 √1.0. Simplifying, t = 0.5 x 1.0 = 0.5 seconds.
Similarly, for a player who jumps 0.3 m vertically, we have h = 0.3 m and plugging it into the equation, we get t = 0.5 √0.3. Simplifying, t = 0.5 x 0.55 = 0.275 seconds.
Therefore, the basketball player who jumps 1.0 m off the floor has a hang time of 0.5 seconds, while the player who jumps 0.3 m off the floor has a hang time of 0.275 seconds.