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Write the following in standard form for a parabola.
x² −4x + 2y + 12=0

User Ejd
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Final answer:

To write the equation x² - 4x + 2y + 12 = 0 in standard form for a parabola, rearrange the equation to isolate the x terms and complete the square. The standard form is (x - 2)² = -2y - 8.

Step-by-step explanation:

The given equation is x² - 4x + 2y + 12 = 0.

To write this equation in standard form for a parabola, we need to isolate the terms involving x on one side of the equation. Rearranging the equation, we get x² - 4x = -2y - 12.

Next, we can complete the square for the x terms by adding the square of half the x coefficient. Half of -4 is -2, so we add (-2)² = 4 to both sides of the equation, resulting in x² - 4x + 4 = -2y - 8.

Finally, we can rewrite the left side of the equation as a perfect square: (x - 2)². So, the standard form of the parabola equation is (x - 2)² = -2y - 8.

User MrCarrot
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