Final answer:
The potential solutions of ln(x² - 25) = 0 are x = √26 and x = -√26.
Step-by-step explanation:
To find the potential solutions of ln(x² - 25) = 0, we can rewrite the equation as e^0 = x² - 25, since ln(x) = y is the inverse of e^y = x. Simplifying, we have 1 = x² - 25. Rearranging the equation, we get x² = 26. Taking the square root of both sides, we find that x = ±√26. Therefore, the potential solutions are x = √26 and x = -√26.