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There are 215.0 mol of an unknown gas stored at a temperature of 1110 K in a large, 395 L container. R=0.0821 L·atm/(mol·K)

User Infeligo
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The unknown gas stored in a 395 L container at a temperature of 1110 K exerts a pressure of approximately 5251.365 atm, based on the ideal gas law equation PV = nRT.

To find the pressure exerted by the unknown gas, we can use the ideal gas law equation: PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature.

Given:

Number of moles (n) = 215.0 mol

Temperature (T) = 1110 K

Volume (V) = 395 L

Gas constant (R) = 0.0821 L·atm/(mol·K)

Substituting the given values into the ideal gas law equation:

P * 395 L = 215.0 mol * 0.0821 L·atm/(mol·K) * 1110 K

Simplifying:

P = (215.0 mol * 0.0821 L·atm/(mol·K) * 1110 K) / 395 L

P = 5251.365 atm

Therefore, the pressure exerted by the unknown gas is approximately 5251.365 atm.

User Aung Thiha
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