Question

Find the discriminant. 3q²+q+5=0 How many real solutions does the equation have?

Answer 1

no real solutions

Step-by-step explanation:

given a quadratic equation in standard form

ax² + bx + c = 0 ( a ≠ 0 ), then the discriminant is

b² - 4ac

• if b² - 4ac > 0 , then 2 real and irrational solutions

• if b² - 4ac > 0 and a perfect square , then 2 real and rational solutions

• if b² - 4ac = 0 , then 2 real and equal solutions

• if b² - 4ac < 0 , then no real solutions

given

3q² + q + 5 = 0 ← in standard form

with a = 3 , b = 1 and c = 5 , then

b² - 4ac = 1² - ( 4 × 3 × 5) = 1 - 60 = - 59

Since b² - 4ac < 0 then the equation has no real solutions

Answer 2

The discriminant is -59 and the equation has no real solutions.

Step-by-step explanation:

This is a quadratic equation in the form ax²+bx+c=0, where a=3, b=1, and c=5. To find the discriminant, we can use the formula: Δ=b²-4ac. Plugging in the values, we get: Δ=(1)²-4(3)(5)=-59.

Since the discriminant is negative, the equation has no real solutions. This means that there are no values of q that will satisfy the equation.