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Assume the base sequence T-A-C-C-C-A-A-A-A-C-A-T is the beginning of a gene. How many codons could be obtained from this sequence? ________.

User Vathymut
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2 Answers

3 votes

Final answer:

The sequence T-A-C-C-C-A-A-A-A-C-A-T can be divided into 4 codons, each consisting of a set of three nucleotides, which correspond to amino acids or signals in the genetic code.

Step-by-step explanation:

The sequence given, T-A-C-C-C-A-A-A-A-C-A-T, contains a length of 12 nucleotides. Because each codon consists of a sequence of three nucleotides, we can determine the number of codons by dividing the total number of nucleotides by three. Thus, for the provided sequence, 12 nucleotides ÷ 3 nucleotides per codon equals 4 codons. This sequence could be translated into a chain of amino acids during protein synthesis, with each codon corresponding to either a specific amino acid or a start/stop signal according to the genetic code.

User Maurits Moeys
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4 votes

Final answer:

A given DNA sequence of 12 nucleotides would produce 4 codons, since each codon includes three nucleotides.

Step-by-step explanation:

The student is asking how many codons could be obtained from the DNA sequence T-A-C-C-C-A-A-A-A-C-A-T. A codon is a sequence of three nucleotide bases which encode a single amino acid in the genetic code.

Given that the sequence provided has 12 nucleotide bases, to calculate the number of codons we divide the total number of nucleotides by three (since each codon is comprised of three nucleotides),

resulting in a total of 4 codons.

User Alfredo
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