The least number of rows needed to seat a group of 23 adults and 45 children, where each row seats 9 people, is 8 rows.
Step-by-step explanation:
The question asks for the least number of rows needed to seat a group of 23 adults and 45 children at a play, with each row being able to seat 9 people. To solve this, first, find the total number of people attending, which is 23 adults plus 45 children, equaling 68 people. Then, divide the total number of people by the number of seats per row. This gives 68 / 9, which equals 7.55. Since you can't have a fraction of a row, you would need 8 full rows to seat everyone.
The least number of rows needed is 8 because you must round up to ensure there is a seat for every person. Remember, no other ticket in the theater can have the same four parts: gate, section, row, and seat number. Each seat is unique and designed to seat one occupant only.