Question

Adjust the window so you can find all of the points of intersection for the system of equations. What are the roots of the original polynomial equation?

a. -6
b. 0
c. 6
d. -4
e. 3
f. 8

Answer 1

To find the roots of the polynomial equation x² + 1.2x - 6 × 10^-3 = 0, we can use the quadratic formula. The roots are approximately 0.782 and -1.582.

Step-by-step explanation:

To find the roots of the polynomial equation x² + 1.2x - 6 × 10-3 = 0, we can use the quadratic formula. For an equation of the form ax² + bx + c = 0, the roots are given by the formula:

x = (-b ± √(b² - 4ac))/(2a)

In this case, the coefficients are a = 1, b = 1.2 × 10-3, and c = -6 × 10-3. Plugging in these values, we get:

x = (-1.2 × 10-3 ± √((1.2 × 10-3)² - 4(1)(-6 × 10-3)))/(2(1))

Simplifying further gives:

x ≈ 0.782 or x ≈ -1.582