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In the Hardy-Weinberg equation, p + q = 1, p and q represent the frequency of both alleles in a population

of diploid organisms if:


Select one:


a. Two or more alleles exist for that gene

b. Two or more genes are needed to express a trait

c. Only two alleles exist for that gene

d. The trait is polygenic

e. None of the above are correct

1 Answer

1 vote

Final answer:

In the Hardy-Weinberg equation, the right answer is 'c. Only two alleles exist for that gene.' With p as the frequency of allele A at 0.4, the frequency of the AA genotype (p²) is 0.4², which is 0.16 or 16%.

Step-by-step explanation:

In the Hardy-Weinberg equation, p + q = 1, where p and q represent the frequency of the two alleles in a population of diploid organisms. The correct statement in this context is that c. Only two alleles exist for that gene.

To answer the Hardy-Weinberg question provided, if p = 0.4, then the frequency of the AA genotype, which is denoted as , can be calculated.

Since p stands for the frequency of the dominant allele A, the calculation for the frequency of the AA genotype would be p² = 0.4² = 0.16, meaning that the frequency of the AA genotype is 0.16 or 16%.

User Lengoman
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