Question

a 100 meter long copper wire has a resistance of 100 ω. another copper wire has the same mass but is 10 meters long. find the resistance of the second wire. group of answer choices 1 ω 10 ω 100 ω 1,000 ω

Answer 1

Since the two wires have the same mass, their resistivities will be the same. Hence, The resistance of the second wire is 10 ω.

Step-by-step explanation:

To find the resistance of the second wire, we can use the formula:

R = (ρ × L) / A

Where R is the resistance, ρ is the resistivity of the material, L is the length of the wire, and A is the cross-sectional area of the wire.

Since the two wires have the same mass, their resistivities will be the same.

As the second wire is 10 meters long, its resistance can be found by substituting the values into the formula:

R2 = (100 ω × 10 m) / 100 m = 10 ω

Therefore, the resistance of the second wire is 10 ω.