34.2k views
3 votes
Find the x - and y-intercepts of the line 14x+16y=-16.

2 Answers

2 votes

Answer:

x - intercept = -
(8)/(7) , y- intercept = - 1

Step-by-step explanation:

to find the x- intercept , let y = 0 in the equation and solve for x

14x + 16(0) = - 16

14x + 0 = - 16

14x = - 16 ( divide both sides by 14 )

x =
(-16)/(14) = -
(8)/(7)x- intercept

to find the y- intercept , let x = 0 in the equation and solve for y

14(0) + 16y = - 16

0 + 16y = - 16

16y = - 16 ( divide both sides by 16 )

y = - 1 ← y- intercept

User Saboor Awan
by
7.9k points
5 votes

Final answer:

To find the x- and y-intercepts of the line 14x + 16y = -16, we can set y = 0 and solve for x to find the x-intercept, which is (-8/7, 0). We can also set x = 0 and solve for y to find the y-intercept, which is (0, -1).

Step-by-step explanation:

To find the x- and y-intercepts of the line 14x + 16y = -16, we can use the standard forms of the line equation.

To find the x-intercept, we set y = 0 and solve for x. We have: 14x + 16(0) = -16 → 14x = -16 → x = -16/14 = -8/7.

Therefore, the x-intercept is (-8/7, 0).

To find the y-intercept, we set x = 0 and solve for y. We have: 14(0) + 16y = -16 → 16y = -16 → y = -16/16 = -1.

Therefore, the y-intercept is (0, -1).

User Vineeth Chitteti
by
8.1k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories