Question

−5x+y−48=0 Plot the point on the line with the x-coordinate x=−10
.

Answer 1

The point on the line with the x-coordinate
`\(x = -10\)` is
`\((-10, -2)\)`

To plot the point on the line with the x-coordinate
`\(x = -10\)`, we need to find the corresponding y-coordinate on the given line.

The equation of the line is
`\(-5x + y - 48 = 0\)`. We can substitute
`\(x = -10\)` into this equation and solve for y:

`\[ -5(-10) + y - 48 = 0 \]`

Simplifying the equation:

`\[ 50 + y - 48 = 0 \]`

`\[ y = -2 \]`

So, when
`\(x = -10\)`, the corresponding y-coordinate is
`\(y = -2\)`.

Therefore, the point on the line with the x-coordinate
`\(x = -10\)` is
`\((-10, -2)\)`.