Question

Math help, thank you so much!

Answer 1

(a)
`\sf f(2) = 3`

(b)
`\sf f(-1) = -3`

(c)
`\sf f(a) = a^2 + a - 3`

Explanation:

To evaluate the function
`\sf f(x) = x^2 + x - 3` for specific values, substitute the given values into the function.

(a)
`\sf f(2)`:

`\sf f(2) = (2)^2 + 2 - 3 = 4 + 2 - 3 = 3`

(b)
`\sf f(-1)`:

`\sf f(-1) = (-1)^2 - 1 - 3 = 1 - 1 - 3 = -3`

(c)
`\sf f(a)`:

`\sf f(a) = a^2 + a - 3`

So, the evaluations are:

(a)
`\sf f(2) = 3`

(b)
`\sf f(-1) = -3`

(c)
`\sf f(a) = a^2 + a - 3`

Answer 2

Given equation: f(x) = x² + x - 3

To find f(x) of something, simply substitute the value inside the equation.

(a) f(2) = (2)² + (2) - 3 = 4 + 2 - 3 = 3

(b) f(-1) = (-1)² + (-1) - 3 = 1 - 1 - 3 = -3

(c) f(a) = a² + (a) - 3 = a² + a - 3