Question

\[14\cdot(-2i+6)=\]

Your answer should be a complex number in the form \[a+bi\] where \[a\] and \[b\] are real numbers.

Answer 1

To find the product of 14 and (-2i+6), we distribute the multiplication to get -28i + 84, which simplifies to the complex number 84 - 28i.

Step-by-step explanation:

To multiply the complex number 14 by -2i+6, we distribute 14 across the terms in the parentheses:

• 14 \(\cdot\) (-2i) = -28i
• 14 \(\cdot\) 6 = 84

Combining these results, we get:

84 - 28i

This is already in the standard form a + bi for a complex number, where a is the real part and b is the coefficient of the imaginary part. Thus, the answer to the multiplication is 84 - 28i.