Question

Find the sum of the first ten terms of this sequence: 16, 8, 4, .... select one:

a. 52
b. 32
c. 36
d. 18

Answer 1

Step-by-step explanation:

to find the sum of the first ten terms of the sequence $16, 8, 4, \ldots$, we need to observe the pattern in the sequence and then apply a formula to calculate the sum. We can notice that each term in the sequence is half of the previous term. So, to find the next term, we divide the previous term by 2. Let's write out the first few terms of the sequence to see the pattern more clearly: 16, 8, 4, 2, 1, 1/2, 1/4. 1/8, 1/16, 1/32

To find the sum of the first ten terms of a geometric sequence, How can I calculate sequence?

Arithmetic Sequence Formula

nth term is, an = a1 + (n - 1) d.

Sum of n terms is, S_n = a(1-r^n)/(1-r)

S_n = the sum of the first n numbers

n = terms, a = first term, r = the common ratio

a=16, r = 1/2, n=10

plug those into the formula and

Final answer is 32.

Answer 2

To find the sum of the first ten terms of the sequence, use the formula for the sum of an arithmetic series: S = (n/2)(a + l).

Step-by-step explanation:

To find the sum of the first ten terms of the sequence 16, 8, 4, ..., we can use the formula for the sum of an arithmetic series.

The formula is: S = (n/2)(a + l), where S is the sum, n is the number of terms, a is the first term, and l is the last term.

In this sequence, the first term a is 16, the common difference is -8 (as each term is half of the previous term), and the number of terms n is 10.

Substituting these values into the formula, we get: S = (10/2)(16 + 4) = 5(20) = 100.

Therefore, the sum of the first ten terms of the sequence is 100.