Question

* Given three ints, a b c, return true if they are in strict increasing

* order, such as 2 5 11, or 5 6 7, but not 6 5 7 or 5 5 7. However, with the
* exception that if "equalOk" is true, equality is allowed, such as
* 5 5 7 or 5 5 5.
*/
public boolean inOrderEqual(int a, int b, int c, boolean equalOk) {
if(equalOk)
return a <= b && b <= c;

return a < b && b < c;
}

Answer 1

The given code implements a method that checks if three integers are in strict increasing order, with the option to allow equality if specified.

Step-by-step explanation:

The given code is implementing a method called inOrderEqual which takes three integers a, b, and c, and a boolean value equalOk. The objective is to check if the three integers are in strict increasing order, with the exception of allowing equality if equalOK is true.

If equalOk is true, the method returns true if a is less than or equal to b and b is less than or equal to c. If equalOk is false, the method returns true only if a is less than b and b is less than c. In other words, if equalOk is false, the integers must be strictly increasing.

For example, if a=2, b=5, and c=11, then the method will return true since 2 < 5 < 11. However, if a=6, b=5, and c=7, the method will return false since 6 is not less than 5.