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3 votes
3 votes
50 points! Mhanifa I need help with #4 and #5 please and thank you! Random answers will be reported so don’t answer if you don’t know it

50 points! Mhanifa I need help with #4 and #5 please and thank you! Random answers-example-1
50 points! Mhanifa I need help with #4 and #5 please and thank you! Random answers-example-1
50 points! Mhanifa I need help with #4 and #5 please and thank you! Random answers-example-2
User Jess Bowers
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2 Answers

14 votes
14 votes

Answer:

If you use the supplementary law you will find they are equal

Explanation:

User Lance Whatley
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3.7k points
9 votes
9 votes

Answer:

#4

PS║RT - given

  • PQ ≅ TQ - given
  • ∠PQS ≅ ∠TQS - vertical angles
  • ∠SPQ ≅ ∠RTQ - alternate interior angles

ΔPSQ ≅ ΔTRQ - ASA Postulate

#5

BD bisects ∠ADC - given

BD⊥AC - given

  • ∠ADB = 1/2∠ADC and ∠CDB = 1/2∠ADC ⇒ ∠ADB ≅ ∠CDB
  • ∠DBA = 90°, ∠DBC = 90° ⇒ ∠DBA ≅ ∠DBC
  • DB ≅ DB - reflexive property

ΔABD ≅ ΔCBD - ASA Postulate

User Ryan Jay
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3.7k points