Answer:
#4
PS║RT - given
- PQ ≅ TQ - given
- ∠PQS ≅ ∠TQS - vertical angles
- ∠SPQ ≅ ∠RTQ - alternate interior angles
ΔPSQ ≅ ΔTRQ - ASA Postulate
#5
BD bisects ∠ADC - given
BD⊥AC - given
- ∠ADB = 1/2∠ADC and ∠CDB = 1/2∠ADC ⇒ ∠ADB ≅ ∠CDB
- ∠DBA = 90°, ∠DBC = 90° ⇒ ∠DBA ≅ ∠DBC
- DB ≅ DB - reflexive property
ΔABD ≅ ΔCBD - ASA Postulate