Question

/* We are having a party with amounts of tea and candy. Return the int

* outcome of the party encoded as 0=bad, 1=good, or 2=great. A party is good
* (1) if both tea and candy are at least 5. However, if either tea or candy
* is at least double the amount of the other one, the party is great (2).
* However, in all cases, if either tea or candy is less than 5, the party is
* always bad (0).
*/
public int teaParty(int tea, int candy)

Answer 1

The probabilities of getting each color jelly bean are calculated by dividing the number of jelly beans of that color by the total number of jelly beans in the jar, which is 150. The steps involve simple division for blue, green, purple, red, yellow, and a subtraction followed by division for orange jelly beans.

Step-by-step explanation:

To calculate the probability of picking a specific color jelly bean from a jar, you can use the formula P(Event) = (Number of favorable outcomes) / (Total number of outcomes). In this case, the total number of jelly beans is 150. Let's find the probability for each color:

Find P(B)

The probability of getting a blue jelly bean, P(B), is the number of blue jelly beans (26) divided by the total number of jelly beans (150). Therefore, P(B) = 26/150.

Find P(G)

The probability of getting a green jelly bean, P(G), is the number of green jelly beans (20) divided by the total number of jelly beans. So, P(G) = 20/150.

Find P(P)

The probability of getting a purple jelly bean, P(P), is the probability of getting a purple jelly bean is the number of purple jelly beans (28) divided by the total. Hence, P(P) = 28/150.

Find P(R)

The probability of getting a red jelly bean, P(R), is calculated similar to the others. P(R) = 22/150.

Find P(Y)

For a yellow jelly bean, P(Y) is 38/150.

Find P(O)

Finally, to find the probability of getting an orange jelly bean, subtract the sum of all other colored jelly beans from the total and then divide by 150. P(O) = (150 - 22 - 38 - 20 - 28 - 26)/150.