Question

he DNA sequence "TAC GGT CAG AAG ATT" will transcribe the mRNA codon sequence "___ ___ ___ ___ ___" (Type in spaces between the codons!): The amino acid sequence that will finally result is "___ ___ ___ ___ ___" (Use first 3 letters of the name for the abbreviation unless it is start or stop, and type spaces between the abbreviations):

Answer 1

The DNA sequence provided translates to the mRNA sequence 'AUG CCA GUC UUC UAA', which codes for an amino acid sequence comprising Met, Pro, Val, Phe, and ending with a stop codon. This process involves transcription of DNA to mRNA and subsequent translation of mRNA into a sequence of amino acids.

Step-by-step explanation:

The student's DNA sequence 'TAC GGT CAG AAG ATT' would transcribe the mRNA codon sequence 'AUG CCA GUC UUC UAA'. Translation of this mRNA sequence into the corresponding amino acid sequence would give Met (Methionine or start), Pro (Proline), Val (Valine), Phe (Phenylalanine), and a stop codon (UAA does not code for any amino acid and signifies the end of translation).

Summarizing the general process: Transcription involves the conversion of a DNA sequence to its complementary mRNA strand, with Adenine (A) pairing with Uracil (U) in RNA instead of Thymine (T). Translation of this mRNA template converts the nucleotides into the amino acids that comprise a protein, with each triplet codon of mRNA corresponding to a single amino acid, as per the genetic code.