Final answer:
Applying the same 25 N force to a 7 kg ball results in a lower acceleration than the 0.25 kg ball, calculated as approximately 3.57 m/s² using Newton's second law of motion.
Step-by-step explanation:
The force F on an object is equal to its mass m multiplied by its acceleration a.
In this case, we are given that a ball accelerates at a rate of 5 m/s when a 25 N force is applied to it.
To find out what happens to the ball's acceleration when the same amount of force is applied to a 7 kg ball, we can use the formula F = ma.
Since the force (F) and mass (m) are the same, the acceleration (a) will be different for the 7 kg ball. Let's calculate it:
For the first ball:
- F = 25 N
- m = 0.25 kg
- Using F = ma, we can solve for a: 25 = 0.25a
- a = 100 m/s²
Now, let's calculate the acceleration for the 7 kg ball:
- F = 25 N
- m = 7 kg
- Using F = ma, we can solve for a: 25 = 7a
- a ≈ 3.57 m/s²
So, when the same amount of force is applied to a 7 kg ball, its acceleration is approximately 3.57 m/s².